Web28 apr. 2024 · # Python program to check if the input year is a leap year or not year = 2000 if (year % 4) == 0: if (year % 100) == 0: if (year % 400) == 0: print ( "{0} is a leap year". … Web9 okt. 2016 · Closed. superbool opened this issue on Oct 9, 2016 · 1 comment. nathanielc closed this as completed on Oct 11, 2016. Sign up for free to join this conversation on …
leap = ((year % 4 == 0) && (year % 100 != 0)) (year % 400 == 0 ...
Web21 jan. 2024 · 以下实例用于判断用户输入的年份是否为闰年: year = int (input ("输入一个年份: ")) if (year % 4) == 0: if (year % 100) == 0: if (year % 400) == 0: print (" {0} 是闰 … Web11 aug. 2024 · I have the following program to find out the leap year year = int (input ("Enter a year: ") if (year % 4 == 0) and (year % 100 == 0) and (year % 400 == 0): print ("True") … check if item exists in ienumerable c#
C语言判断某一年是否为闰年!三种实现程序代码(值得收藏)
WebDeze projector is voorzien van de beste resolutie en is gemakkelijk mee te nemen. Met deze beamer is het mogelijk om Netflix of Youtube te kijken vanaf de beamer zonder te … Web17 nov. 2014 · \u0026 is actually one character, not 6. Change line 3 to . int end = url.indexOf("\u0026"); By the way, I am not sure about your usage of single quotes. I … Web21 mei 2024 · Algorithm for determining a leap year: 1) if the year is divisible by 4 and not divisible by 100, this is a leap year. 2) if the year is divisible by 4 and by 100 but not … check if it is a letter python